abufrejoval said:
Nothing in the argument required the arc to be a semicircle. If the arc has length xxx times the circumference (where x≤1/2x \leq 1/2x≤1/2), each anchor's event has probability xN−1x^{N-1}xN−1 instead of (1/2)N−1(1/2)^{N-1}(1/2)N−1. Mutual exclusivity still holds because the gap is at least 1−x≥1/21 - x \geq 1/21−x≥1/2 of the circumference, too large for any other anchor's arc to bridge:
。WPS下载最新地址对此有专业解读
ОАЭ задумались об атаке на Иран20:55
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On-device capabilities (the ability of your phone to process far more data), edge computing (locally sourced IT technology rather than distant datacenters), more efficient use of available bandwidth (AI-enabled load control), and greater cloud access will all come together to produce a new wireless network.